2015: Problem 17

Topic: Other
Concepts: Dimensional analysis, Kinetic energy


Solution:

Let λ\lambda be the maximum kinetic energy per kilogram that can be stored in the flywheel. If we double the thickness hh of the flywheel, that is equivalent to stacking two flywheels on top of each other. Since each has λ\lambda energy per kilogram, the combination also has λ\lambda energy per kilogram. Hence, λ\lambda is independent of hh.

We can use dimensional analysis to find λ(r,ρ,σ)\lambda(r,\rho,\sigma). First, the dimensions of each variable are:

[λ]=[EM]=ML2/T2M=L2T2[\lambda]=\left[\frac{E}{M}\right]=\frac{ML^2/T^2}{M}=\frac{L^2}{T^2}
[r]=L[r]=L
[ρ]=[MV]=ML3[\rho]=\left[\frac{M}{V}\right]=\frac{M}{L^3}
[σ]=[FA]=ML/T2L2=MLT2[\sigma]=\left[\frac{F}{A}\right]=\frac{ML/T^2}{L^2}=\frac{M}{LT^2}

We need 1 power of σ\sigma to have the correct number of powers of TT:

[σ1]=MLT2[\sigma^1]=\frac{M}{LT^2}

We need 1-1 powers of ρ\rho to cancel out the mass dependence:

[σρ]=MLT2L3M=L2T2\left[\frac{\sigma}{\rho}\right]=\frac{M}{LT^2}\frac{L^3}{M}=\frac{L^2}{T^2}

This has the same dimensions as λ\lambda so there is no rr dependence. Thus,

λ=ασρ\lambda=\frac{\alpha\sigma}{\rho}

where α\alpha is a dimensionless constant, so the answer is E.

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