2009: Problem 10

Topic: Kinematics
Concepts: 5 kinematics equations, Free fall


Solution:

From kinematics, the trajectory of the first apple is

y1(t)=vt12gt2y_1(t)=vt-\frac{1}{2}gt^2

The trajectory of the second apple is

y2(t)=vt12gt2y_2(t)=-vt-\frac{1}{2}gt^2

The displacement between the two apples is then

Δy(t)=y1(t)y2(t)=2vt\Delta y(t)=y_1(t)-y_2(t)=2vt

At t=2st=2\,\mathrm{s}, we have

Δy=2(7m/s)(2s)=28m\Delta y=2(7\,\mathrm{m/s})(2\,\mathrm{s})=28\,\mathrm{m}

so the answer is C.

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1D elastic collision 1D inelastic collision 5 kinematics equations Angular kinematics Atwood machine Buoyant force Circular motion Circular orbits Conservation of angular momentum Conservation of energy Conservation of linear momentum Dimensional analysis Effective spring constant Elliptical orbits Energy dissipation Error propagation Fictitious forces Fma: Collisions Fma: Dynamics Fma: Energy Fma: Fluids Fma: Gravity Fma: Kinematics Fma: Oscillatory Motion Fma: Other Fma: Rigid Bodies Fma: System of Masses Forces in mechanics Free fall Inclined plane Kinetic energy Limiting cases Mass-spring system Moments of inertia Motion graphs Newton's laws Power Projectile motion Relative velocity Rolling motion Simple harmonic motion Statics Torque Torque from weight Work-energy theorem

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