2015: Problems 7-8

Topic: Collisions
Concepts: 1D inelastic collision


Solution:

The initial momentum of the system is

pi=mv0p_i=mv_0

Since the collisions are completely inelastic, all the masses stick together so the final momentum is

pf=(m+3m+9m)vf=13mvfp_f=(m+3m+9m)v_f=13mv_f

Conserving linear momentum pi=pfp_i=p_f,

mv0=13mvfmv_0=13mv_f
vf=v013v_f=\frac{v_0}{13}

so the answer is A.

Topic: Collisions
Concepts: 1D elastic collision


Solution:

Recall that in an elastic collision between mass mm moving at velocity v0v_0 and mass MM at rest, the velocity v2v_2 of MM after the collision is given by

v2=2mm+Mv0v_2=\frac{2m}{m+M}v_0

In our case, we have after mm collides with 3m3m,

v3m=2(m)m+3mv0=v02v_{3m}=\frac{2(m)}{m+3m}v_0=\frac{v_0}{2}

After 3m3m collides with 9m9m, we have

v9m=2(3m)3m+9m(v02)=v04v_{9m}=\frac{2(3m)}{3m+9m}\left(\frac{v_0}{2}\right)=\frac{v_0}{4}

Thus, the answer is B.

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