2014: Problem 2

2014-2

Topic: Rigid Bodies
Concepts: Inclined plane, Newton’s laws


Solution:

Since the ball is rolling down the incline, there is a normal force NN on the ball perpendicular to the incline and a friction force ff on the ball up along the incline. By Newton’s 3rd law, the ball exerts the same forces in the opposite directions on the plane. Thus, the total force F\vec{F} that the ball exerts on the plane is

F=fN\vec{F}=-\vec{f}-\vec{N}

so the answer is E.

Leave a Reply

This site uses Akismet to reduce spam. Learn how your comment data is processed.

Join 259 other subscribers

F=ma Training Program
Group (2026)
Individual (2026)

1D elastic collision 1D inelastic collision 5 kinematics equations Angular kinematics Atwood machine Buoyant force Circular motion Circular orbits Conservation of angular momentum Conservation of energy Conservation of linear momentum Dimensional analysis Effective spring constant Elliptical orbits Energy dissipation Error propagation Fictitious forces Fma: Collisions Fma: Dynamics Fma: Energy Fma: Fluids Fma: Gravity Fma: Kinematics Fma: Oscillatory Motion Fma: Other Fma: Rigid Bodies Fma: System of Masses Forces in mechanics Free fall Inclined plane Kinetic energy Limiting cases Mass-spring system Moments of inertia Motion graphs Newton's laws Power Projectile motion Relative velocity Rolling motion Simple harmonic motion Statics Torque Torque from weight Work-energy theorem

Discover more from Kevin S. Huang

Subscribe now to keep reading and get access to the full archive.

Continue reading