2014: Problem 18

2014-18

Topic: Dynamics
Concepts: Atwood machine, Statics


Solution:

The tension from the two strings must balance the weight of the pulley. We have

TC2TB=MpgT_C-2T_B=M_pg

The tension from the three strings must balance the weight of the box:

TA+TBTC=MbgT_A+T_B-T_C=M_bg

Adding these two equations, we obtain

TATB=(Mp+Mb)gT_A-T_B=(M_p+M_b)g

We could have directly obtained this by considering the external forces on the pulley-box system. Note the difference in tensions between TAT_A and TBT_B is constant. Thus,

TATB=30N20N=10NT_A-T_B=30\,\mathrm{N}-20\,\mathrm{N}=10\,\mathrm{N}

If TBT_B increases to 30N30\,\mathrm{N}, then TA=TB+10N=40NT_A=T_B+10\,\mathrm{N}=40\,\mathrm{N} so the answer is B.

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