2009: Problem 16

Topic: Oscillatory Motion
Concepts: CM frame, Effective spring constant, Mass-spring system


Solution:

We go to the CM frame, where both masses oscillate about their midpoint. If we look at one of the masses (the other mass is the mirror reflection), it behaves as a mass-spring system with a half-spring. Since cutting a spring in half doubles the spring constant ke=2kk_e=2k,

ω=kem=2km\omega=\sqrt{\frac{k_e}{m}}=\sqrt{\frac{2k}{m}}

so the answer is B.

Leave a Reply

This site uses Akismet to reduce spam. Learn how your comment data is processed.

Join 256 other subscribers

F=ma Training Program
Group (2026)
Individual (2026)

1D elastic collision 1D inelastic collision 5 kinematics equations Angular kinematics Atwood machine Buoyant force Circular motion Circular orbits Conservation of angular momentum Conservation of energy Conservation of linear momentum Dimensional analysis Effective spring constant Elliptical orbits Energy dissipation Error propagation Fictitious forces Fma: Collisions Fma: Dynamics Fma: Energy Fma: Fluids Fma: Gravity Fma: Kinematics Fma: Oscillatory Motion Fma: Other Fma: Rigid Bodies Fma: System of Masses Forces in mechanics Free fall Inclined plane Kinetic energy Limiting cases Mass-spring system Moments of inertia Motion graphs Newton's laws Power Projectile motion Relative velocity Rolling motion Simple harmonic motion Statics Torque Torque from weight Work-energy theorem

Discover more from Kevin S. Huang

Subscribe now to keep reading and get access to the full archive.

Continue reading