Kevin S. Huang

2007: Problem 22

Topic: Energy
Concepts: Kinetic energy, Work-energy theorem

Solution:

Since a constant force $F$ acts on the rocket over a distance $d$ , the work done on the rocket is $W=Fd$ . By the work-energy theorem, this is equal to the kinetic energy gained by the rocket,

W=Fd=\Delta K=\frac{p^2}{2m}

p=\sqrt{2Fdm}

If the same force $F$ acts over the same distance $d$ but the mass $m$ is increased by a factor of $9$ , then the momentum $p$ increases by a factor of $3$ so the answer is D.

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2007, F=ma Exam

Fma: Energy, Kinetic energy, Work-energy theorem

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